My daughter was given the following task: given the first number x and the second number y, find the n^{th} number. The description was quite vague, but my daughter managed to do the task.

Can you?

**Example**

Turns out, for x = 7, y = 10 and n = 5,

the output should be

nthPlace(x, y, n) = 19.

**Input/Output**

**[time limit] 4000ms (js)**

**[input] integer x**The first number.

*Constraints:*

1 ≤ x ≤ y.**[input] integer y**The second number.

*Constraints:*

x ≤ y ≤ 100.**[input] integer n**The number to find.

*Constraints:*

3 ≤ n ≤ 50.**[output] integer**The n

^{th}number.

**Solution**

The solution is simply \(n-1\) times the difference of the upper and lower bound plus the lower bound:

\[s = x + (y - x) \cdot (n - 1)\]

Or as a JavaScript solution:

```
nthPlace = (x, y, n) =>
x + (y - x) * --n
```