Codingame Solution: Mars Lander - Episode 1

Built as a game, the simulator puts Mars Lander on a limited zone of Mars sky.

Every second, depending on the current flight parameters (location, speed, fuel ...), the program must provide the new desired tilt angle and thrust power of Mars Lander: The game simulates a free fall without atmosphere. Gravity on Mars is 3.711 m/s² . For a thrust power of X, a push force equivalent to X m/s² is generated and X liters of fuel are consumed. As such, a thrust power of 4 in an almost vertical position is needed to compensate for the gravity on Mars.

For a landing to be successful, the ship must:

• land on flat ground
• land in a vertical position (tilt angle = 0°)
• vertical speed must be limited ( ≤ 40m/s in absolute value)
• horizontal speed must be limited ( ≤ 20m/s in absolute value)

Remember that this puzzle was simplified:

• the landing zone is just below the shuttle. You can therefore ignore rotation and always output 0 as the target angle.
• you don't need to store the coordinates of the surface of Mars to succeed.
• you only need your vertical landing speed to be between 0 and 40m/s – your horizontal speed being nil.
• As the shuttle falls, the vertical speed is negative. As the shuttle flies upward, the vertical speed is positive.

The program must first read the initialization data from standard input. Then, within an infinite loop, the program must read the data from the standard input related to Mars Lander's current state and provide to the standard output the instructions to move Mars Lander.

Initialization input

Line 1: the number surfaceN of points used to draw the surface of Mars.
Next surfaceN lines: a couple of integers landXlandY providing the coordinates of a ground point. By linking all the points together in a sequential fashion, you form the surface of Mars which is composed of several segments. For the first point, landX = 0 and for the last point, landX = 6999

Input for one game turn

A single line with 7 integers: XYhSpeedvSpeedfuelrotatepower

• X,Y are the coordinates of Mars Lander (in meters).
• hSpeed and vSpeed are the horizontal and vertical speed of Mars Lander (in m/s). These can be negative depending on the direction of Mars Lander.
• fuel is the remaining quantity of fuel in liters. When there is no more fuel, the power of thrusters falls to zero.
• rotate is the angle of rotation of Mars Lander expressed in degrees.
• power is the thrust power of the landing ship.

Output for one game turn

A single line with 2 integers: rotatepower :

• rotate is the desired rotation angle for Mars Lander. Please note that for each turn the actual value of the angle is limited to the value of the previous turn +/- 15°.
• power is the desired thrust power. 0 = off. 4 = maximum power. Please note that for each turn the value of the actual power is limited to the value of the previous turn +/- 1.

Constraints

2 ≤ surfaceN < 30
0 ≤ X < 7000
0 ≤ Y < 3000
-500 < hSpeed, vSpeed < 500
0 ≤ fuel ≤ 2000
-90 ≤ rotate ≤ 90
0 ≤ power ≤ 4
Response time per turn ≤ 100ms

 

var N = parseInt(readline());
for (var i = 0; i < N; i++) {
    var inputs = readline().split(' ');
}

while (true) {
    var inputs = readline().split(' ');
    var VS = parseInt(inputs[3]);

    if (VS <= -40)
        print('0 4');
    else 
        print("0 0")
}