Given integers \(b\) and \(a\), find the smallest integer \(h\) such that there exists a triangle of height \(h\), base \(b\) , having an area of at least \(a\) .

**Input Format**

In the first and only line, there are two space-separated integers \(b\) and \(a\), denoting respectively the base of a triangle and the desired minimum area.

**Constraints**

- \(1\leq b\leq 10^6\)
- \(1\leq a\leq 10^6\)

**Output Format**

In a single line, print a single integer \(h\) , denoting the minimum height of a triangle with base \(b\) and area at least \(a\) .

**Sample Input 0**

`2 2`

**Sample Output 0**

`2`

**Explanation 0**

The task is to find the smallest integer height of the triangle with base \(2\) and area at least \(2\) . It turns out, that there are triangles with height \(2\) , base \(2\) and area \(2\) , for example a triangle with corners in the following points: \((1,1),(3,1), (1,3)\) :

It can be proved that there is no triangle with integer height smaller than \(2\) , base \(2\) and area at least \(2\) .

**Sample Input 1**

`17 100`

**Sample Output 1**

`12`

**Explanation 1**

The task is to find the smallest integer height of the triangle with base \(17\) and area at least \(100\) . It turns out, that there are triangles with height \(12\), base \(17\) and area \(102\), for example a triangle with corners in the following points: \((2,2), (19,2), (16,14)\) .

It can be proved that there is no triangle with integer height smaller than \(12\) , base \(17\) and area at least \(100\) .

## Solution

The area of the triangle can be determined as \(a = \frac{1}{2} bh\) from which follows that the height can be calculated as \(h = \frac{2a}{b}\). Since we are looking for an integer solution with \(\geq a\), we can ceil the calculation and can implement the solution in Ruby:

```
def lowestTriangle(base, area)
(2 * area / base).ceil
end
base, area = gets.split.map(&:to_f)
p lowestTriangle(base, area)
```