The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
Solution
The sum of the square is:
\[f(n) = \sum\limits_{i=1}^n i^2 = \frac{1}{6} n (n+1) (2 n+1)\]
The square of the sum is:
\[g(n) = \left(\sum\limits_{i=1}^n i\right)^2 = \frac{1}{4} n^2 (n+1)^2\]
The difference:
\[\begin{array}{rl} f(n) - g(n) &= \frac{1}{6} n (n+1) (2 n+1) - \frac{1}{4} n^2 (n+1)^2\\ &= \frac{1}{12} n (n + 1) (3 n^2 - n - 2)\end{array}\]
And the final JS solution:
function solution(n) {
return n * (n + 1) * (3 * n * n - n - 2) / 12;
}